Newbie like question

Hi

How do I run Multiple Likes in one query? Do I need to run each Like
seperately?

Thanks for any help.Sorry. I don't think that was clear. What I meant was I need something that
is similar to:

Select * from Security..SecUser
where UserId in (123, 456, 789)

The following query does not work:

Select * from Security..SecUser
where UserId like ('%123%', '%456%', '%789%')

Is there a query that can do this?

Thanks again|||You can use logical operators to join two tables; put the patterns you
want to match in one table, and join it to the source table. Here's an
example:

--Table with data that I want to look for a pattern in
DECLARE @.Root TABLE (KeyVal int,
Root varchar(10))

INSERT INTO @.Root
SELECT 1, 'ABCDEF'
UNION ALL
SELECT 2, 'DEFGHI'
UNION ALL
SELECT 3, '123ABC'
UNION ALL
SELECT 4, '123DEF'

--Table of patterns
DECLARE @.LikeTest TABLE (LikeTest varchar(10))
INSERT INTO @.LikeTest
SELECT 'ABC'
UNION ALL
SELECT 'DEF'
UNION ALL
SELECT 'XYZ'

--Results; note that I used DISTINCT to return a single value for each
match.
SELECT DISTINCT r.KeyVal, r.Root
FROM @.Root r JOIN @.LikeTest l ON r.Root LIKE '%' + l.LikeTest + '%'

HTH,
Stu|||Alternatively:

Select * from Security..SecUser
where
UserId like '%123%'
or UserId like '%456%'
or UserId like '%789%'

Obviously, if you have a ton of them, it'll be a pain to type them all
out.|||Thanks for the help, guys. That was much appreciated!!

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